ANSWER: The rules you understand including the one to your price use simply if the charges should be thought of as a continuous fluid that pass on in itself out on any surface, no matter how highest, and also zero thickness. Needless to say, a case as you identify, with 5 excess electrons is within absolutely no way for example a liquid and that i perform reckon that anything from 5-0 so you’re able to 0-5 could be the delivery more a time. The theory is that, the 5 electrons would arrange by themselves making sure that each try since far away regarding the other cuatro as you are able to, however, indeed there wouldn’t be a different sort of such as for instance distribution.
QUESTION: Could it possibly be it is possible to to help you suspend an electron thru electrostatic levitation during the a beneficial uniform magnetic industry? Incase the current are decreased adequate so that the electrostatic force for the electron is actually less than the fresh new push on account of new electron’s pounds Sugar Daddy Sites dating apps do the latest electron up coming experience a good ‘fall’ owed to help you the law of gravity?
I’m asking this because I’m curious if the placing a positron within the an effective uniform magnetized career (in vacuum pressure) and you may reducing the current to help you a very small value making sure that the latest electrostatic force is leaner compared to weight would produce a positron so you’re able to together with feel an excellent ‘fall’. Assuming it did feel a trip it could be ascertained whether it do fall up otherwise down.
Of the inertial size After all the fresh new ratio of push you apply at they separated because of the the acceleration, this means that their resistance to becoming accelerated
I’m 17 years old plus in the united kingdom planning to study physics during the school in sep and you will was just interested in learning that it just like the our information this year is electricity phenomena and you may i chatted about millikan’s oils miss check out and that looked a comparable style of suspension system if electrostatic force and force on account of gravity was well-balanced.
Now, we know to over the top accuracy that inertial mass away from a good positron is equivalent to new inertial size from an enthusiastic electron
ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a “magnetic field” you should say “electric field”; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever “weighed” a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let’s talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6×10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6×10 -19 ?6×10 -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6×10 -22 C/m 2 which would correspond to an electron density on the plates of about 6×10 -22 /1.6×10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual field much less than your 6×10 -11 V/m. Back to the drawing board! Keep asking those hard and interesting questions, though, and good luck with your university studies.